C program to print all repeated elements in an array and also print the count of repeated numbers

 Write a program to print all repeated elements in an array and also print the count of repeated numbers

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Example:

input:
Enter the number of element: 4
Enter Elements: 10
20
10
20
output:
The duplicate number is: 10
The duplicate number is: 20

The total number of the duplicate element is: 2

Algorithm of this program:

1. Initially, we define the size of the array.
2. Then, take a user-input size of the array and scan the element of the array.
3. For finding the duplicate number in the array we have to run two for loops.
4. The first for loop scan all elements from 0 index
5. The next for loops run from i+1 so that it checks all the duplicate elements.
6. If any duplicate element is found, we print the duplicate number and count it.
7. At last, we print the count of all the duplicate numbers present in the array.
8. The return type of the main function is int so, in the last, we return 0.

Program of the problem:

//Write a program to print all repeated elements in an array and also print the count of //repeated numbers

#include <stdio.h>

#define SIZE 100  

int main(){

    int arr[SIZE];

    int size;

    int count = 0;

    printf("Enter the number of elements in array: ");

    scanf("%d", &size);

    printf("Enter the value of elements in array: ");

    for(int i=0; i<size; i++){

        scanf("%d", &arr[i]);

    }

    for(int i=0; i<size; i++){

        for(int j=i+1; j<size; j++){

            if(arr[i] == arr[j]){

                printf("The duplicate numbers is: %d\n", arr[i]);

                count++;

                break;

            }

        }

    }

    printf("\nTotal number of duplicate elements found in array = %d", count);

    return 0;

}

//code is contributed by paagalblogger.blogspot.com

Output:

Hope! it helps 🙏