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For loop Hackerrank Solution in C++

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 For loop Hackerrank Solution in C++


Problem-5:-

A for loop is a programming language statement which allows code to be repeatedly executed.

The syntax for this is

for ( <expression_1> ; <expression_2> ; <expression_3> )
    <statement>
  • expression_1 is used for intializing variables which are generally used for controlling terminating flag for the loop.
  • expression_2 is used to check for the terminating condition. If this evaluates to false, then the loop is terminated.
  • expression_3 is generally used to update the flags/variables.

A sample loop will be

for(int i = 0; i < 10; i++) {
    ...
}

Input Format

You will be given two positive integers,  and  (), separated by a newline.

Output Format

For each integer  in the interval  :

  • If , then print the English representation of it in lowercase. That is "one" for , "two" for , and so on.
  • Else if  and it is an even number, then print "even".
  • Else if  and it is an odd number, then print "odd".

Note: 

Sample Input

8
11

Sample Output

eight
nine
even
odd

Solution-

#include <iostream>
#include <cstdio>
using namespace std;

int main() {
    string arr[11] = {"even","one","two","three","four","five",
                      "six","seven","eight","nine","odd"};
    int a,b;
    cin>>a>>b;

    if((a>=1 && a<=9) && (b>=1 && b<=9)){
        for(int n=a; n<=b; n++)
        {
            cout<<arr[n] <<endl;
        }
    }
    else if((a>=1 && a<=9) && (b>9))
    {
        for(int n=a; n<=9; n++){
            cout<<arr[n] <<endl;
        }
        for(int n=10; n<=b; n++){
            if(n%2==0){
                cout<<arr[0] <<endl;
            }
            else{
                cout<<arr[10] <<endl;
            }
        }        
    }
    else{
        for(int n=a; n<=b; n++){
           if(n%2==0){
                cout<<arr[0] <<endl;
            }
            else{
                cout<<arr[10] <<endl;
            } 
        }
    }
    return 0;
}


Explanation:-

In this Question, the idea is you are given two numbers 'a' and 'b' such that a<=b. You then need to test every number from a to b and output either the text version of the variable (if number <=9) or whether the value is even or odd (if number > 9).

So basically when the inputs are 7,11 you need to test every integer from 7 to 11, so you need to test 7,8,9,10,& 11. This leads to the output specified in the "Sample Output" of  "seven, eight, nine, even, odd".


Hackerrank Completion Proof:-



Hope, it Helps!!

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