Function Hackerrank Solution in C++

Problem-6:-

Functions are a bunch of statements glued together. A function is provided with zero or more arguments, and it executes the statements on it. Based on the return type, it either returns nothing (void) or something.

A sample syntax for a function is

return_type function_name(arg_type_1 arg_1, arg_type_2 arg_2, ...) {
    ...
    ...
    ...
    [if return_type is non void]
        return something of type `return_type`;
}

For example, a function to read four variables and return the sum of them can be written as

int sum_of_four(int a, int b, int c, int d) {
    int sum = 0;
    sum += a;
    sum += b;
    sum += c;
    sum += d;
    return sum;
}

You have to write a function int max_of_four(int a, int b, int c, int d) which reads four arguments and returns the greatest of them.

+= : Add and assignment operator. It adds the right operand to the left operand and assigns the result to the left operand.
a += b is equivalent to a = a + b;

Input Format

Input will contain four integers - , one in each line.

Output Format

Print the greatest of the four integers.
PS: I/O will be automatically handled.

Sample Input

Sample Output

Solution:-

#include <iostream>
#include <cstdio>
using namespace std;

int max_of_four(int a, int b, int c, int d){
    if(a>b){
        if(a>c){
            if(a>d){
                return a;
            }
            else
            {
                return d;
            }
        }
        else{
            if(c>d){
                return c;
            }
            else{
                return d;
            }
        }
    }
    else{
        if(b>c){
            if(b>d){
                return b;
            }
            else{
                return d;
            }
        }
        else{
            return c;
        }
    }
}

int main() {
    int a, b, c, d;
    scanf("%d %d %d %d", &a, &b, &c, &d);
    int ans = max_of_four(a, b, c, d);
    printf("%d", ans);
    
    return 0;
}

Explanation:

In this program, we use the concept of Nested 'If-else' statement

Hackerrank Completion Proof:-

Hope, it Helps!!

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