Java Loops I Hackerrank solution in Java

Problem-6:-

Objective
In this challenge, we're going to use loops to help us do some simple math.

Task
Given an integer, , print its first  multiples. Each multiple  (where ) should be printed on a new line in the form: N x i = result.

Input Format

A single integer, .

Constraints

Output Format

Print  lines of output; each line  (where ) contains the  of  in the form:
N x i = result.

Sample Input

2

Sample Output

2 x 1 = 2
2 x 2 = 4
2 x 3 = 6
2 x 4 = 8
2 x 5 = 10
2 x 6 = 12
2 x 7 = 14
2 x 8 = 16
2 x 9 = 18
2 x 10 = 20

Solution:-

import java.io.*;

import java.math.*;

import java.security.*;

import java.text.*;

import java.util.*;

import java.util.concurrent.*;

import java.util.regex.*;

public class Solution {

    private static final Scanner scanner = new Scanner(System.in);

    public static void main(String[] args) {

        int N = scanner.nextInt();

        scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");

        for(int i=1; i<=10; i++){

            int result=N*i;

            System.out.println(N + " x " + i + " = " + result);

            //or we use System.out.printf("%d x %d = %d", N, i, N*i);

            // in this case you don't need to declare result.

        }

        scanner.close();

    }

}

Hackerrank Completion Proof:-

Hope, it Helps!!